A girl walks 20 meters towards North. Then, turning to her left, she walks 50 meters. Then, turning to her right, she walks 40 metres. Again, she turns to her right and walks 50 metres. How far is she from her initial position?

60 metres

The correct answer is Option (1) → 60 metres

Step-by-Step Movement Analysis:

1. Starts at (0, 0): The girl begins at her initial position.
2. Walks 20 meters North: She moves from $(0, 0)$ to $(0, 20)$.
3. Turns left and walks 50 meters: Turning left from North means moving West. She moves from $(0, 20)$ to $(-50, 20)$.
4. Turns right and walks 40 meters: Turning right from West means moving North again. She moves from $(-50, 20)$ to $(-50, 60)$ (calculated as $20 + 40 = 60$).
5. Turns right and walks 50 meters: Turning right from North means moving East. She moves from $(-50, 60)$ to $(0, 60)$ (calculated as $-50 + 50 = 0$).

Final Distance Calculation:

The girl's final position is $(0, 60)$, and her initial position was $(0, 0)$.

• The horizontal distance ($x$-axis) is $0$.
• The vertical distance ($y$-axis) is $60$ meters.

The distance between the two points is exactly 60 meters.