Practicing Success
A sells a cycle to B at a profit of 20% and B sells it to C at a loss of 25%. If C bought the cycle for ₹ P, then the cost price of it for A was. |
₹ \(\frac{1}{20}\) P ₹ \(\frac{9}{10}\) P ₹ \(\frac{9}{20}\) P ₹ \(\frac{10}{9}\) P |
₹ \(\frac{10}{9}\) P |
A → B → C 5 6 (@20% profit) 4 3 (@25% loss)
Now, making B equal in both case: A → B → C 5 (× 4) 6 (× 4) 4 (× 6) 3 (× 6) 20 24 18 ↓ P (given) Here, ⇒ 18R ⇒ P ⇒ CP of A = 20R → \(\frac{20P}{18}\) = \(\frac{10P}{9}\) |