CUET Preparation Today
$\frac{2x_3}{4}+8≥2+\frac{4x}{3}$ |
$(-∞, 4.3]$ $(-∞, 7.3]$ $(-∞, 6.3]$ $(-∞, 5.3]$ |
$(-∞, 6.3]$ |
The correct answer is option (3) : $(-∞, 6.3]$ $\frac{2x_3}{4}+8≥2+\frac{4x}{3}$ Multiplying by 12 (LCM of 4, 3) both the sides $3(2x-3)+96≥24+16x$ $6x-16x≥24-87$ $-10x≥-63$ $x≤6.3$ ∴ Solution set is $(-∞, 6.3]$ |
