Practicing Success
Two parallel plate capacitors of capacitances 2 µF and 3 µF are joined in series and the combination is connected to a battery of V volts. The values of potential across the two capacitors $V_1$ and $V_2$ and energy stored in the two capacitors $U_1$ and $U_2$ respectively are related as ________. Fill in the blank with the correct answer from the options given below. |
$\frac{V_1}{V_2}=\frac{U_1}{U_2}=\frac{3}{2}$ $\frac{V_1}{V_2}=\frac{U_1}{U_2}=\frac{2}{3}$ $\frac{V_1}{V_2}=\frac{3}{2}$ and $\frac{U_1}{U_2}=\frac{2}{3}$ $\frac{V_1}{V_2}=\frac{2}{3}$ and $\frac{U_1}{U_2}=\frac{3}{2}$ |
$\frac{V_1}{V_2}=\frac{U_1}{U_2}=\frac{3}{2}$ |
$ V_1 = \frac{C_2 V}{C_1 + C_2} = \frac{3V}{5}$ $ V_2 = \frac{C_1 V}{C_1 + C_2} = \frac{2V}{5}$ $\Rightarrow \frac{V_1}{V_2} = \frac{3}{2}$ $ U_1 = \frac {q^2}{2C_1}, U_2 = \frac{q^2}{2C_2} \Rightarrow \frac{U_1}{U_2} = \frac{C_2}{C_1} = \frac{3}{2}$ The correct answer is Option (1) → $\frac{V_1}{V_2}=\frac{U_1}{U_2}=\frac{3}{2}$ |