Present ages of A and B are in the ratio of 3 : 2. If the present age of C is 45 years and A's present age is \(\frac{4}{5}\) of C's present age, then after how many years the ages of A and B would be in the ratio of 15 : 11?
Answer & explanation
Correct answer: option 3
C = 45 years
A = 45 × \(\frac{4}{5}\) = 36 years
Ratio of present age of A and B = 3x : 2x
⇒ 3x = 36 ⇒ x = 12
Hence, B'age = 2x ⇒ x = 24 years
ATQ, let time is t years:
⇒ \(\frac{36\;+\;t}{24\;+\;t}\) = \(\frac{15}{11}\)
⇒ 396 + 11t = 360 + 15t
⇒ 4t = 36
⇒ t = 9