If lattice parameter for a crystalline structure is 3.6 Å, then atomic radius in fcc crystal in Å is –
Answer & explanation
Correct answer: option 3
Atomic radius for fcc crystal is
$r=\frac{a}{2\sqrt{2}}=\frac{3.6}{2\sqrt{2}}Å=1.27Å$
If lattice parameter for a crystalline structure is 3.6 Å, then atomic radius in fcc crystal in Å is –
Correct answer: option 3
Atomic radius for fcc crystal is
$r=\frac{a}{2\sqrt{2}}=\frac{3.6}{2\sqrt{2}}Å=1.27Å$