n biscuits are distributed among N beggars at random. The probability that a particular beggar gets r( <n) biscuits, is
Answer & explanation
Correct answer: option 1
Since a biscuit can be given to any one of N beggars. Therefore, each biscuit can be distributed in N ways. So, the total number of ways of distributed n biscuits among N beggars is
$N × N × .....× N = N^n$
n - times
Now, r biscuits can be given to a particular beggar in ${^nC_r}$, ways and the remaining (n-r) biscuits can be distributed to (N − 1) beggars in $(N-1)^{n-r}$ - ways. Thus, the number of ways in which a particular beggar receives r biscuits is
${^nC_r} × (N-1)^{n-r}$
Hence, required probability $=\frac{^nC_r ×(N-1)^{n-r}}{N^n}$