Practicing Success
n biscuits are distributed among N beggars at random. The probability that a particular beggar gets r( <n) biscuits, is |
${^nC}_r \left(\frac{1}{N}\right)^r \left(\frac{N-1}{N}\right)^{n-r}$ $\frac{^nC_r}{N^r}$ ${^nC_r}$ $\frac{r}{n}$ |
${^nC}_r \left(\frac{1}{N}\right)^r \left(\frac{N-1}{N}\right)^{n-r}$ |
Since a biscuit can be given to any one of N beggars. Therefore, each biscuit can be distributed in N ways. So, the total number of ways of distributed n biscuits among N beggars is $N × N × .....× N = N^n$ n - times Now, r biscuits can be given to a particular beggar in ${^nC_r}$, ways and the remaining (n-r) biscuits can be distributed to (N − 1) beggars in $(N-1)^{n-r}$ - ways. Thus, the number of ways in which a particular beggar receives r biscuits is ${^nC_r} × (N-1)^{n-r}$ Hence, required probability $=\frac{^nC_r ×(N-1)^{n-r}}{N^n}$ |