On a new scale of temperature (which is linear) and called the W scale, the freezing and boiling points of water are 39° W and 239° W respectively. What will be the temperature on the new scale, corresponding to a temperature of 39° C on the Celsius scale?
Answer & explanation
Correct answer: option 3
\(\frac{39-0}{100-0} = \frac{x - 39}{239-39}\)
x = 117°W