Practicing Success
Practicing Success
CUET Preparation Today
Let $\vec{a}, \vec{b}, \vec{c}$ be three unit vectors such that $\vec{a}+5 \vec{b}+3 \vec{c}=\vec{0}$ Then $\vec{a} .(\vec{b} \times \vec{c})$ is equal to: |
$\vec{a} . \vec{b}$ $\vec{a} . (\vec{b}+2 \vec{c})$ $\vec{b} . (\vec{a}+\vec{c})$ None of these |
None of these |
$\vec{a}+5 \vec{b}+3 \vec{c}=\vec{0}$ Thus $\vec{a}, \vec{b}, \vec{c}$ are coplaner. Hence $\vec{a} .(\vec{b} \times \vec{c})=0$ Hence (4) is correct answer. |
