The length and breadth of a room are 15m, 17 cm and 9m, 2 cm respectively.  How many square tiles will cover the area of the floor of this room (minimum)?

814

Number of Square Tiles = \(\frac{Area\;of\;the\;floor}{Area\;of\;one\;tile}\)

Sides of a tile = HCF of 1517 cm & 902 cm = 41

Nunber of square tiles = \(\frac{1517 × 902}{41 × 41}\) = 31 × 22 = 814 Tiles (minimum)