CUET Preparation Today
CUET
General Test
Quantitative Reasoning
Trigonometry
It $cot θ=\frac{3}{\sqrt{5}}, 0° < θ > 90°,$ then the value of $\frac{6sec^θ-\frac{5}{3}cosec^2θ}{\frac{3}{5}sec^2θ+\frac{4}{3}cosec^2θ}$, is equal to :
$\frac{2}{3}$
1
$\frac{1}{2}$
$\frac{1}{3}$
