The mean of the following probability distribution is: X = x 0 1 2 P(…

X = x	0	1	2
P(X = x)	1//4	1//2	1//4

We know that mean of probability distribution

is → ∑x_iP(x_i)

x_i → data point P(x_i) → probability of respective data point

for given distribution 

mean (µ) = $0 \times \frac{1}{4}+1 \times \frac{1}{2}+2 \times \frac{1}{4}$

$= 0 + \frac{1}{2} + \frac{1}{2}$

µ = 1