The correct sequence of reactions to convert benzene to 3-bromobenzamine is: |
nitration, reduction, bromination reduction, nitration, bromination nitration, bromination, reduction bromination, nitration, reduction |
nitration, bromination, reduction |
The correct answer is option 3. nitration, bromination, reduction. To convert benzene to 3-bromobenzamide, the following steps and reasoning must be considered: Step 1: Nitration of Benzene The nitration of benzene is typically performed using a mixture of concentrated nitric acid (HNO₃) and concentrated sulfuric acid (H₂SO₄). This reaction introduces a nitro group (\(-NO_2\)) to the benzene ring, resulting in nitrobenzene
Step 2: Bromination of Nitrobenzene The bromination can be carried out using bromine (\(Br_2\)) in the presence of a catalyst such as iron (Fe) or iron(III) bromide (FeBr₃). The nitro group is a meta-directing group, meaning that when bromination occurs, the bromine will add to the meta position relative to the nitro group, resulting in 3-bromo nitrobenzene.
Step 3: Reduction of 3-Bromo-Nitrobenzene The reduction can be done using catalytic hydrogenation (H₂ in the presence of a catalyst like palladium or platinum) or other reducing agents like tin (Sn) with hydrochloric acid (HCl). This step will convert the nitro group (\(-NO_2\)) to an amine group (\(-NH_2\)), yielding 3-bromoaniline (or 3-bromobenzamine).
Thus, the correct sequence of reactions to convert benzene to 3-bromobenzamine is: Nitration, Bromination, Reduction |