Practicing Success
A can do a piece of work in 30 days. He completed 40% of the work and then left. B completed the remaining work in 21 days. Working together, A and B will complete 65% of the same work in: |
13 days 10 days $10\frac{1}{2}$ days $13\frac{1}{2}$ days |
$10\frac{1}{2}$ days |
A = 30 days, Take efficiency of A as 1, Total work = 1 x 30 = 30 units, A did 40% of the work and left = 40% of 30 = 12 units, Remaining work = 30 - 12 = 18 units, ⇒ B complete 18 units in 21 days = \(\frac{18}{21}\) = \(\frac{6}{7}\) (Efficiency of B) ⇒ Time required by A + B to complete 65% of the total work i.e; 19.5 units of work = \(\frac{19.5}{1+6/7}\) = \(\frac{21}{2}\) = \( {10 }_{ 2}^{1 } \) days, ..(\(\frac{Work}{Efficiency}\) = Time) |