Given that mean of a normal variable X is 12 and standard deviation is 4, then find the Z-score of data point 20. |
1 2 -2 4 |
2 |
The correct answer is Option (2) → 2 Given $μ = 12$ and $σ = 4$ $∵x = 20$ $∴ Z=\frac{x-μ}{σ}=\frac{20-12}{4}$ $=\frac{8}{4}= 2$ |