If a particle is dropped from a height X. The de-Broglie wavelength of the particle as a function of height is proportional to: |
$\sqrt{X}$ $X^{-1/2}$ $X^0$ $X$ |
$X^{-1/2}$ |
The correct answer is Option (2) → $X^{-1/2}$ According to De-Broglie, $λ=\frac{h}{P}=\frac{h}{mv}$ $λ=\frac{h}{m(\sqrt{2×9.8x})}$ $[v^2=u^2+2as]$ $∴λ∝X^{-1/2}$ |