If 64 added in a number then the number becomes 157\(\frac{1}{7}\)% of itself. Find the number. |
100 115 112 114 |
112 |
157\(\frac{1}{7}\) % = 100 % + 57\(\frac{1}{7}\)% ATQ, 57\(\frac{1}{7}\)% = 64 57\(\frac{1}{7}\)% = \(\frac{4}{7}\) Here, ATQ, 4R = added number = 64 1R = 16 7R = original number = 7 x 16 = 112 |