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The amplitude of the magnetic field of a harmonic electromagnetic wave in vacuum is $B_o= 610 nT$. The amplitude of the electric field of the wave is: |
$5 × 10^{14} NC^{-1}$ $203 × 10^{-17} NC^{-1}$ $183 NC^{-1}$ $610 NC^{-1}$ |
$183 NC^{-1}$ |
The correct answer is Option (3) → $183 NC^{-1}$ The relationship between the electric field $(E_o)$ and the magnetic field $B_o$ is, $E_o=CB_o$ $=(3×10^8)×(610×10^{-9})$ $=183V/m$ |
