The product \('Y'\) in the following reaction sequence is

The correct answer is option 4. 

In the first step, we will react the benzyl chloride with the potassium cyanide with the aqueous ethanol which will form benzyl cyanide and potassium chloride.

Then in the next step, the cyanide will get reduced to amine when we react with the benzyl cyanide with the \(LiAlH_4\).

The compound \(Y\) is \(2-Phenylethanamine\).