The sides AB, BC and AC of a $\triangle$ABC are 12 cm, 8 cm and 10 cm respectively. A circle is inscribed in the triangle touching AB, BC and AC at D, E and F, respectively. The difference between the lengths of AD and CE is:
Answer & explanation
Correct answer: option 2
As we know,
AD = AF, FC = CE and BE = BD [Tangents]
Let AD = x and CE = y
BD = 12 - x
BE = 12 - x
CE = BC - BE
y = 8 - 12 + x
y = x - 4
or x - y = 4
AD - CE = 4 cm