A dry cell delivering 2 A has terminal voltage 1.41V. What is the internal resistance of the cell if its open–circuit voltage is 1.59 V?

$ 5.09\Omega$ $ 6.09\Omega$ $ 7.09\Omega$ $ 0.09\Omega$

$ 0.09\Omega$

Open circuit voltage = E = 1.59V  $ V = E - Ir $ $ \Rightarrow 1.41 = 1.59 - 2 r $ $\Rightarrow r = \frac{0.18}{2} = 0.09 \Omega$