Practicing Success
Practicing Success
CUET Preparation Today
If \(\frac{sin^2 θ }{tan^2 θ - sin^2 θ}\) = 3 and 0° < θ < 90° , then value of θ is? |
15° 45° 60° 30° |
30° |
\(\frac{sin^2 θ}{tan^2 θ - sin^2 θ}\) = 3 ⇒ sin2 θ = 3(tan2 θ - sin2 θ) ⇒ 4sin2 θ = 3tan2 θ ⇒ 4sin2 θ = \(\frac{3sin^2 θ}{cos^2 θ}\) ⇒ cos2 θ = \(\frac{3}{4}\) ⇒ cosθ = \(\frac{\sqrt {3 }}{2}\) ⇒ cosθ = \(\frac{\sqrt {3 }}{2}\) ⇒ θ = 30° |
