An 800-metre-long train can pass a stationary pole completely in 72 seconds. A 1200-metre-long train can also pass a stationary pole completely in 72 seconds. If both the trains are running in the same direction, then the faster train, coming from behind the slower train, can cross the slower train in how much time?
Answer & explanation
Correct answer: option 2
Speed of train 1 = \(\frac{Distance}{Time}\)
= \(\frac{800}{72}\) = \(\frac{100}{9}\) m/sec
Speed of train 2 ( faster train) = \(\frac{1200}{72}\) = \(\frac{50}{3}\) m/sec
Relative speed when they moves in same direction = \(\frac{50}{3}\) - \(\frac{100}{9}\) = \(\frac{50}{9}\) m/sec
Time taken by faster train to cross slower train = \(\frac{2000 × 9 }{50}\)
= 360 seconds