CUET Preparation Today
Functions $f, g : R \to R$ are defined, respectively, by $f(x) = x^2 + 3x + 1$, $g(x) = 2x - 3$, find $gof$. |
$4x^2 - 6x + 1$ $2x^2 + 6x - 1$ $2x^2 + 3x - 2$ $2x^2 + 6x + 5$ |
$2x^2 + 6x - 1$ |
The correct answer is Option (2) → $2x^2 + 6x - 1$ ## Given that, $f(x) = x^2 + 3x + 1, g(x) = 2x - 3$ $gof(x) = g\{f(x)\} = g(x^2 + 3x + 1)$ $= 2(x^2 + 3x + 1) – 3$ $= 2x^2 + 6x + 2 - 3 = 2x^2 + 6x – 1$ |
