Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Electrostatic Potential and Capacitance

Question:

A cube of side 'a' has a charge Q at each of its vertices, what is the potential due to this charge array at the centre of the cube?

Options:

$\frac{2Q}{\sqrt{3}πε_0a}$

$\frac{4Q}{\sqrt{3}πε_0a}$

$\frac{Q}{2\sqrt{3}πε_0a}$

$\frac{8Q}{\sqrt{3}πε_0a^2}$

Correct Answer:

$\frac{4Q}{\sqrt{3}πε_0a}$

Explanation:

The correct answer is Option (2) → $\frac{4Q}{\sqrt{3}πε_0a}$