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The order and degree of the equation $1 +(\frac{d^2y}{dx^2})^{5/2}=(\frac{dy}{dx})^2$ are respectively |
2, 5 2, 1 1, 1 doesn’t exist |
2, 5 |
The given differential equation can be re-written as $[(\frac{dy}{dx})^2-1]^2=(\frac{d^2y}{dx^2})^5$. Hence its order is 2 and degree is 5. Hence (A) is the correct answer. |
