The order and degree of the equation $1 +(\frac{d^2y}{dx^2})^{5/2}=(\frac{dy}{dx})^2$ are respectively
Answer & explanation
Correct answer: option 1
The given differential equation can be re-written as $[(\frac{dy}{dx})^2-1]^2=(\frac{d^2y}{dx^2})^5$.
Hence its order is 2 and degree is 5.
Hence (A) is the correct answer.