The order and degree of the equation $1 +(\frac{d^2y}{dx^2})^{5/2}=(\frac{dy}{dx})^2$ are respectively

2, 5 2, 1 1, 1 doesn’t exist

2, 5

The given differential equation can be re-written as $[(\frac{dy}{dx})^2-1]^2=(\frac{d^2y}{dx^2})^5$. Hence its order is 2 and degree is 5. Hence (A) is the correct answer.