CUET Preparation Today
A coin is tossed 5 times. The probability of getting atleast one head is : |
$\frac{31}{32}$ $\frac{15}{16}$ $\frac{1}{32}$ $\frac{63}{64}$ |
$\frac{31}{32}$ |
The correct answer is Option (1) → $\frac{31}{32}$ P (at least one Head) = 1 - P (No heads) $=1-(\frac{1}{2})^5=1-\frac{1}{32}$ $=\frac{31}{32}$ |
