A coin is tossed 5 times. The probability of getting atleast one head is :
Answer & explanation
Correct answer: option 1
The correct answer is Option (1) → $\frac{31}{32}$
P (at least one Head) = 1 - P (No heads)
$=1-(\frac{1}{2})^5=1-\frac{1}{32}$
$=\frac{31}{32}$