If 60% of a number is 120 more than 20% of the number, then 28% of the number is less than 33\(\frac{1}{3}\)% of the number by:
Answer & explanation
Correct answer: option 4
Let the number = Z
ATQ,
⇒ 60% of Z - 20% of Z = 120
⇒ 40% of Z = 120
⇒ 1% of Z = 3
⇒ 100% of Z = 300
Now,
⇒ 33\(\frac{1}{3}\) % of Z - 28 % of Z
= 5\(\frac{1}{3}\)% of Z
= \(\frac{16}{300}\) x 300 = 16