If 60% of a number is 120 more than 20% of the number, then 28% of the number is less than 33\(\frac{1}{3}\)% of the number by: |
12 14 15 16 |
16 |
Let the number = Z ATQ, ⇒ 60% of Z - 20% of Z = 120 ⇒ 40% of Z = 120 ⇒ 1% of Z = 3 ⇒ 100% of Z = 300 Now, ⇒ 33\(\frac{1}{3}\) % of Z - 28 % of Z = 5\(\frac{1}{3}\)% of Z = \(\frac{16}{300}\) x 300 = 16 |