For an equilateral prism, it is found that angle of minimum deviation is equal to angle of the prism. Find the refractive index of material of the prism.
Answer & explanation
Correct answer: option 4
The correct answer is Option (4) → $\sqrt{3}$
The refractive index (μ) is given by -
$μ=\frac{\sin\left(\frac{60+60}{2}\right)}{\sin\left(\frac{A}{2}\right)}$
where,
$D_{min}$ = Angle of Minimum deviation
$μ=\frac{\sin\left(\frac{60+60}{2}\right)}{\sin\left(\frac{60}{2}\right)}=\frac{\sin 60°}{\sin 30°}$
$μ=\sqrt{3}$