For an equilateral prism, it is found that angle of minimum deviation is equal to angle of the prism. Find the refractive index of material of the prism.

$\sqrt{3}$

The correct answer is Option (4) → $\sqrt{3}$

The refractive index (μ) is given by -

$μ=\frac{\sin\left(\frac{60+60}{2}\right)}{\sin\left(\frac{A}{2}\right)}$

where,

$D_{min}$ = Angle of Minimum deviation

$μ=\frac{\sin\left(\frac{60+60}{2}\right)}{\sin\left(\frac{60}{2}\right)}=\frac{\sin 60°}{\sin 30°}$

$μ=\sqrt{3}$