Is sinx - 3cosx = √3 cos x, then the value of cot x is ___________.

sinx - 3cox = √3 cosx

tanx - 3 = √3

tanx = 3 + √3 

cotx = \(\frac{1}{tanx}\)

= \(\frac{1}{3 + √3}\)

= \(\frac{1}{3 + √3}\)

= \(\frac{1}{3 + √3}\) ×  \(\frac{3 - √3}{3 - √3}\)

= \(\frac{3 - √3}{6}\)