Practicing Success
Practicing Success
CUET Preparation Today
For $x<\frac{1}{2}$, derivative of $\tan ^{-1}\left(\frac{1+2 x}{1-2 x}\right)$ with respect to $\sqrt{1+4 x^2}$ is: |
$\frac{2 x}{1+4 x^2}$ $\frac{1}{2 x \sqrt{1+4 x^2}}$ $\frac{1}{x \sqrt{1+4 x^2}}$ $2 x \sqrt{1+4 x^2}$ |
$\frac{1}{2 x \sqrt{1+4 x^2}}$ |
The correct answer is Option (2) → $\frac{1}{2 x \sqrt{1+4 x^2}}$ |
