Practicing Success
In Young's double slit experiment the intensity at a point where path difference is $λ/6$ is I. If $I_o$ denotes the maximum intensity, then $I/I_o$ is equal to : |
$\frac{1}{\sqrt{2}}$ $\frac{\sqrt{3}}{2}$ $\frac{3}{4}$ $\frac{1}{2}$ |
$\frac{3}{4}$ |
The correct answer is Option (3) → $\frac{3}{4}$ |