CUET Preparation Today
The value of $tan^{-1}\sqrt{3}-sec^{-1}(-2)+cosec^{-1}\frac{2}{\sqrt{3}}$, is |
$\frac{\pi}{3}$ $\frac{-\pi}{3}$ 0 $\frac{4\pi}{3}$ |
0 |
$tan^{-1}\sqrt{3}-sec^{-1}(-2)+cosec^{-1}\frac{2}{\sqrt{3}}=\frac{\pi}{3}-\frac{2\pi}{3}+\frac{\pi}{3}=0$ |
