Practicing Success

Target Exam

CUET

Subject

-- Mathematics - Section B1

Chapter

Inverse Trigonometric Functions

Question:

The  value of $tan^{-1}\sqrt{3}-sec^{-1}(-2)+cosec^{-1}\frac{2}{\sqrt{3}}$, is

Options:

$\frac{\pi}{3}$

$\frac{-\pi}{3}$

0

$\frac{4\pi}{3}$

Correct Answer:

0

Explanation:

$tan^{-1}\sqrt{3}-sec^{-1}(-2)+cosec^{-1}\frac{2}{\sqrt{3}}=\frac{\pi}{3}-\frac{2\pi}{3}+\frac{\pi}{3}=0$