Statement-1: If $A = \begin{bmatrix}3&-3&4\\2&-3&4\\0&-1&1\end{bmatrix}$, then $adj (adj\, A)= A$
Statement-2: If A is a square matrix of order n, then $adj (adj\, A) =|A|^{n-2}A$
Answer & explanation
Correct answer: option 1
We have,
$adj (adj\, A) |=|A|^{(n-1)^2}$, if A is a square matrix of order n.
If $A = \begin{bmatrix}3&-3&4\\2&-3&4\\0&-1&1\end{bmatrix}$, then $|A|=1$
$∴adj (adj\, A) =|A|^{n-2} A⇒ adj (adj\, A) = A$