Statement-1: If $A = \begin{bmatrix}3&-3&4\\2&-3&4\\0&-1&1\end{bmatrix}$, then $adj (adj\, A)= A$

Statement-2: If A is a square matrix of order n, then $adj (adj\, A) =|A|^{n-2}A$

Statement-1 is True, Statement-2 is true; Statement-2 is a correct explanation for Statement-1.

We have,

$adj (adj\, A) |=|A|^{(n-1)^2}$, if A is a square matrix of order n.

If $A = \begin{bmatrix}3&-3&4\\2&-3&4\\0&-1&1\end{bmatrix}$, then $|A|=1$

$∴adj (adj\, A) =|A|^{n-2} A⇒ adj (adj\, A) = A$