A circle is inscribed in a triangle ABC. It touches sides AB, BC and AC at points R, P and Q, respectively. If AQ = 3.5 cm, PC 4.5 cm and BR = 7 cm, then the perimeter (in cm) of the triangle ΔABC is:
Answer & explanation
Correct answer: option 1
As, tangents drawn from same point on the circle are equal.
AQ = AR = 3.5 cm
CQ = CP = 4.5 cm
BP = BR = 7 cm
Perimeter = AB + BC + CA
= Perimeter = AQ + CQ + CP + BP + BR + AR
= Perimeter = 3.5 + 4.5 + 4.5 + 7 + 7 + 3.5
Therefore, perimeter is 30 cm.