Practicing Success

Target Exam

CUET

Subject

General Test

Chapter

Logical and Analytical Reasoning

Topic

Mathematical Operations

Question:

Which of the following interchange of signs and numbers would make the given equation correct?

12 ÷ 4 + 2 – 6 × 3  =  3 ÷ 12 + 6 × 2 – 4 

Options:

÷ and +, 6 and 4

– and +, 6 and 4

× and ÷, 4 and 6

× and –, 4 and 6

Correct Answer:

÷ and +, 6 and 4

Explanation:

From option (1)

12 ÷ 4 + 2 – 6 × 3  =  3 ÷ 12 + 6 × 2 – 4

⇒ 12 + 6 ÷ 2 – 4 × 3  =  3 + 12 ÷ 4 × 2 – 6

⇒ 12 + 3 – 12  =  3 + 3 × 2 – 6

⇒ 15 – 12  =  3 + 6 – 6

⇒ 3  =  3  (L.H.S. = R.H.S.)