Pipes A and B together can fill an empty tank in $6\frac{2}{3}$ minutes. If A takes 3 minutes more than B to fill the tank, then the time(in minutes) in which A alone would fill one-third part of the tank is:

5

Let \(\frac{1}{3}\) of tank, A can empty the tank in = 5min,

Complete tank empty by A = 15 min,

So, B empty the tank in 15 - 3 = 12 min,

⇒ Time required by A to fill \(\frac{1}{3}\)rd of tank alone = \(\frac{1}{3}\) x 60 = 20 units,

⇒ \(\frac{20}{4}\) = 5 mins.