If \(\frac{a}{1}\) = \(\frac{b}{9}\

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Target Exam

CUET

Subject

General Test

Chapter

Quantitative Reasoning

Topic

Algebra

Question:

If \(\frac{a}{1}\) = \(\frac{b}{9}\) = \(\frac{c}{2}\)

then find (\(\frac{a + b + c}{b + c }\)).

Options:

\(\frac{32}{11}\)

\(\frac{12}{11}\)

\(\frac{2}{11}\)

\(\frac{13}{10}\)

Correct Answer:

\(\frac{12}{11}\)

Explanation:

Given, \(\frac{a}{1}\) = \(\frac{b}{9}\) = \(\frac{c}{2}\)

Here we can directly conclude that

a = 1, b = 9, c = 2, hence

⇒ (\(\frac{a + b + c}{b + c }\)) = (\(\frac{1 + 9 + 2}{ 9 + 2 }\))= \(\frac{12}{11}\)