If a/1 = b/9 = c/2 then find ( (a + b + c)/(b + c ) ).

Given, \(\frac{a}{1}\) = \(\frac{b}{9}\) = \(\frac{c}{2}\)

Here we can directly conclude that 

a = 1, b = 9, c = 2, hence

⇒ (\(\frac{a + b + c}{b + c }\)) = (\(\frac{1 + 9 + 2}{ 9 + 2 }\)) = \(\frac{12}{11}\)