The area bounded by the curve $y = \sqrt{x}$, Y-axis and between the lines $y = 0$ and $y = 3$ is

$9$

The correct answer is Option (3) → $9$

$\text{Area} = \int_{0}^{3} x \, dy$

$= \int_{0}^{3} y^2 \, dy$

$\text{Since, } x = y^2$

$= \left[ \frac{y^3}{3} \right]_{0}^{3} = \left[ \frac{3^3}{3} - 0 \right] = 9$

$\text{Area} = 9 \text{ sq. units}$