The area bounded by the curve $y = \sqrt{x}$, Y-axis and between the lines $y = 0$ and $y = 3$ is
Answer & explanation
Correct answer: option 3
The correct answer is Option (3) → $9$
$\text{Area} = \int_{0}^{3} x \, dy$
$= \int_{0}^{3} y^2 \, dy$
$\text{Since, } x = y^2$
$= \left[ \frac{y^3}{3} \right]_{0}^{3} = \left[ \frac{3^3}{3} - 0 \right] = 9$
$\text{Area} = 9 \text{ sq. units}$