$\int \frac{(x+\sqrt{x})}{2 \sqrt{x}} d x=$
Answer & explanation
Correct answer: option 4
The correct answer is Option (4) - $\frac{x \sqrt{x}}{3}+\frac{x}{2}+C$ (Here C is an arbitrary constant)
$\int \frac{(x+\sqrt{x})}{2 \sqrt{x}} d x=\int \frac{\sqrt{x}}{2}+\frac{1}{2}dx$
$=\frac{x\sqrt{x}}{3}+\frac{x}{2}+C$