Find the differential equation of the family of curves y = Ae2x + B.e2x.
Answer & explanation
Correct answer: option 1
$y=Ae^{2x}+Be^{2x}$
so $y'=2Ae^{2x}+2Be^{2x}$
$y''=4(Ae^{2x}+Be^{2x})$
$y''-4y$
Find the differential equation of the family of curves y = Ae2x + B.e2x.
Correct answer: option 1
$y=Ae^{2x}+Be^{2x}$
so $y'=2Ae^{2x}+2Be^{2x}$
$y''=4(Ae^{2x}+Be^{2x})$
$y''-4y$