There is a circle with centre O and diameter PQ. R is the point on circumference of the circle such that ∠QOR = 60°, then what is the value of ∠RPQ (in degrees)?

30° 45° 55° 60°

30°

∠RPQ = \(\frac{∠QOR}{2}=\frac{60}{2}\) = 30° Angle formed at centre is double the angle formed at circumference.