What is the maximum value of \(P=6x+8y\), when the conditions are: \(2x+y\leq 30; x+2y\leq 24; x\geq 0; y\geq 0\)
Answer & explanation
Correct answer: option 2
$Z(max)=Z(12,6)$
$=6×12+8×6$
$=72+46$
$=120$
What is the maximum value of \(P=6x+8y\), when the conditions are: \(2x+y\leq 30; x+2y\leq 24; x\geq 0; y\geq 0\)
Correct answer: option 2
$Z(max)=Z(12,6)$
$=6×12+8×6$
$=72+46$
$=120$