Match List-I with List-II
| List-I | List-II | ||
| A | Units digit of 11! | I | 1 |
| B | Units digit of $(5)^{500}$ | II | 0 |
| C | Units digit of $(99)^{99}$ | III | 5 |
| D | Units digit of $(3)^{300}$ | IV | 9 |
Choose the correct answer from the options given below :
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → A-II, B-III, C-IV, D-I
$11!=(11×9×8×7×6×5×4×3×2)×10$
⇒ Unit digit = 0
$5^{500}=(5^2)^{250}=(25)^{250}$
⇒ Unit digit = 5
$(99)^{99}⇒((99)^2)^{48}.99$
⇒ Unit digit = 9
$(3)^{300}=(3^4)^{75}$
⇒ Unit digit = 1