Target Exam

CUET

Subject

-- Applied Mathematics - Section B2

Chapter

Probability Distributions

Question:

A sample consists of four observations 1, 3, 5, 7. Then its variance is:

Options:

4

$\frac{20}{3}$

5

3

Correct Answer:

5

Explanation:

$\bar{x}=\frac{1+3+5+7}{4}=4$

$\text{Variance}=\frac{(1-4)^2+(3-4)^2+(5-4)^2+(7-4)^2}{4}$

$=\frac{9+1+1+9}{4}=\frac{20}{4}=5$

$\text{Variance}=5$