CUET Preparation Today
CUET
-- Applied Mathematics - Section B2
Probability Distributions
A sample consists of four observations 1, 3, 5, 7. Then its variance is:
4
$\frac{20}{3}$
5
3
$\bar{x}=\frac{1+3+5+7}{4}=4$
$\text{Variance}=\frac{(1-4)^2+(3-4)^2+(5-4)^2+(7-4)^2}{4}$
$=\frac{9+1+1+9}{4}=\frac{20}{4}=5$
$\text{Variance}=5$