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A current of 2 ampere is passed in a coil of radius 0.5 m and number of turns 20. The magnetic moment of the coil is |
$0.314\, Am^2$ $3.14\, Am^2$ $314\, Am^2$ $31.4\, Am^2$ |
$31.4\, Am^2$ |
Magnetic Moment $M = NIA = NI \pi r^2 = 20 \times 2 \times \pi \times 0.5^2 = 31.4 Am^2$ |
