As a result of change in the magnetic flux linked with the closed loop shown in the figure, an emf of V volt is induced in the loop. The work done (in joule) in taking a charge Q coulomb once along the loop is:

QV

The correct answer is Option (1) → QV

The work done in taking a charge Q once along the loop in the presence of an induced emf V.

Work done, $W=Q×V$ Joules