Solution of $\frac{dy}{dx}=2^{y-x}$ is :
Answer & explanation
Correct answer: option 3
The correct answer is Option (3) → $2^{-y}-2^{-x}=k$
$\frac{dy}{dx}=\frac{2^y}{2^x}$
$⇒\int\frac{1}{2^y}dy=\int\frac{1}{2^x}dx$
$⇒2^{-y}-2^{-x}=k$ [k = constant]
Solution of $\frac{dy}{dx}=2^{y-x}$ is :
Correct answer: option 3
The correct answer is Option (3) → $2^{-y}-2^{-x}=k$
$\frac{dy}{dx}=\frac{2^y}{2^x}$
$⇒\int\frac{1}{2^y}dy=\int\frac{1}{2^x}dx$
$⇒2^{-y}-2^{-x}=k$ [k = constant]