Practicing Success

Target Exam

CUET

Subject

General Test

Chapter

Quantitative Reasoning

Topic

Trigonometry

Question:

The value of $\frac{\sin 30^{\circ} \sin 60^{\circ}}{\cos 60^{\circ} \cos 30^{\circ}}-\tan 45^{\circ}$ is:

Options:

5

0

$\frac{2-\sqrt{2}}{2}$

2

Correct Answer:

0

Explanation:

\(\frac{sin30º. sin60º}{cos60º.cos30º}\) - tan45º 

{ using sinA = cosB  Iff A + B = 90º }

= \(\frac{sin30º. sin60º}{sin30º.sin60º}\) - tan45º

= \(\frac{1}{1}\) - 1

= 1