Practicing Success
Practicing Success
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The value of integral \(\int_1^52^x\,dx=?\) is-
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-30/log(2) -30/log(5) 30/log(5) 30/log(2) |
30/log(2) |
We have integral \(\int_1^52^x\,dx=?\) $2^x = e^{xlog 2}$ ⇒ $\int_1^5e^{xlog 2} dx=\frac{2^x}{log2}$ for x = 1 to x= 5 = $\frac{2^5 - 2^1}{log2} = \frac{30}{log2}$
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